What's the purpose of having a separate "operator new[]" ?

Posted by sharptooth on Stack Overflow See other posts from Stack Overflow or by sharptooth
Published on 2010-03-23T12:43:03Z Indexed on 2010/03/23 13:13 UTC
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Looks like operator new and operator new[] have exactly the same signature:

void* operator new( size_t size );
void* operator new[]( size_t size );

and do exactly the same: either return a pointer to a big enough block of raw (not initialized in any way) memory or throw an exception.

Also operator new is called internally when I create an object with new and operator new[] - when I create an array of objects with new[]. Still the above two special functions are called by C++ internally in exactly the same manner and I don't se how the two calls can have different meanings.

What's the purpose of having two different functions with exactly the same signatures and exactly the same behavior?

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